With an actual voltage of 362 kV on a 345 kV bus, what is the p.u. voltage?

With an actual voltage of 362 kV on a 345 kV bus, what is the p.u. voltage?

• A. 98.0
• B. 105.0
• C. 110.0
• D. 90.0

Answer: (B)

To determine the per unit (p.u.) voltage, you take the actual voltage and divide it by the base voltage, then multiply by 100 to express it as a percentage. In this case, the actual voltage is 362 kV, and the base voltage (in this instance, corresponding to the 345 kV bus) is 345 kV. The calculation is performed as follows: 1. Calculate the per unit (p.u.) voltage: \( \text{p.u. voltage} = \left( \frac{\text{actual voltage}}{\text{base voltage}} \right) \times 100 \) 2. Plugging the respective values into the formula: \( \text{p.u. voltage} = \left( \frac{362 \text{ kV}}{345 \text{ kV}} \right) \times 100 \) 3. Performing the division: \( \frac{362}{345} \approx 1.0507 \) 4. Converting to percentage: \( 1.0507 \times 100 \approx 105.07 \) Rounding appropriately, this yields a p.u. voltage of approximately 105.0. Thus

To determine the per unit (p.u.) voltage, you take the actual voltage and divide it by the base voltage, then multiply by 100 to express it as a percentage. In this case, the actual voltage is 362 kV, and the base voltage (in this instance, corresponding to the 345 kV bus) is 345 kV.

The calculation is performed as follows:

1. Calculate the per unit (p.u.) voltage:

( \text{p.u. voltage} = \left( \frac{\text{actual voltage}}{\text{base voltage}} \right) \times 100 )

2. Plugging the respective values into the formula:

( \text{p.u. voltage} = \left( \frac{362 \text{ kV}}{345 \text{ kV}} \right) \times 100 )

3. Performing the division:

( \frac{362}{345} \approx 1.0507 )

4. Converting to percentage:

( 1.0507 \times 100 \approx 105.07 )

Rounding appropriately, this yields a p.u. voltage of approximately 105.0. Thus